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It wont be necessary
We already know that Enrique is a choker
i need a program to extract the end results of sports from a website into excel or whatever mainframe program use
then with that stats recorded, i want it to compute, manipulate to advance stats about the possibilities of each match, point under such cir stances and extraordinary events for that game/per point serve/match
my friend has 4 years of womens tennis results that he uses to analyse a players trend while watching the games live tv to make his conclusion whether to live bet or not....
anyway is the above possible?
It wont be necessary
We already know that Enrique is a choker
I coded it for you in C.
Code:char*_ = "'""/*";#include <stdio.h>#define m 21#define o(l, k) for(l=0; l<k; l++)#define n(k) o(T, k) int E,L,O,R,G[42][m],h[2][42][m],g[3][8],c [42][42][2],f[42]; char d[42]; void v( int b,int a,int j){ printf("\33[%d;%df\33[4%d" "m ",a,b,j); } void u(){ int T,e; n(42)o( e,m)if(h[0][T][e]-h[1][T][e]){ v(e+4+e,T+2 ,h[0][T][e]+1?h[0][T][e]:0); h[1][T][e]=h[ 0][T][e]; } fflush(stdout); } void q(int l ,int k,int p){ int T,e,a; L=0 ; O=1; while(O ){ n(4&&L){ e= k+c[l] [T][0]; h[0][L-1+c[l][ T][1]][p?20-e:e]=-1; } n(4){ e=k+c[l][T][0]; a=L+c[l][T][1]+1; if(a==42 || h[0][a][p?20-e:e]+1){ O=0; } } n(4){ e= k+c[l][T][0]; h[0][L + c[l][T][1]][p?20-e: e]=g[1][f[p?19+l:l]]; } L++;u(); } n(42) { o(e,m)if(h[0][T][e]<0)break;o(a, m&&e==m){ for(L=T; L; L--) { h[0][L][a]=h[0][L-1] [a ]; } h[0][0][a]=-1; } } u();}int main(){ int T,e,t,r,i,s ,D,V,K; printf("\33[2J\33[?25l"); n(8)g[i=1][T]=7-T; R--; n(42) o(e,m) G[T][e]--; while(fgets(d,42,stdin)) { r=++R; n(17){ e=d[T]-48; d[T]=0; if ((e&7)==e) { g[0][e] ++; G[R][T+2]=e; }} } n(8)if(g[0][7-T]){ t=g[i ][O]; g[i][O++]=g[i][T]; g[i][T]=t; } n(8)g[2][g[i][T]]=T; n(R+i)o(e,m )if(G[T][e]+i) G[T][e]=g[2][G[T][e]]; n(19)o(t,2){ f[T+t+T]=(T["+%#,4" "5>GP9$5-,#C?NX"]-35)>>t*3&7; o(e,4){ c[T][e][t]=("5'<$=$8)Ih$=h9i8'9" "t=)83)l4(99(g9>##>4(" [T+t+T]-35)>>e*2&3;} } n(15) { s=T>9?m:(T&3)-3?15:36;o(e,s)o(t,2)c[T+19][e][t]="6*6,8*6.608.6264826668\865::(+;0(6+6-6/8,61638065678469.;88))()3(6,8*6.608.6264826668865:+;4)-*6-6/616365,\-6715690.5;,89,81+,(023096/:40(8-7751)2)65;695(855(+*8)+;4**+4(((6.608.626482666886\5:+;4+4)0(8)6/61638065678469.;88)-4,4*8+4(((60(/6264826668865:+;4-616365676993-9:54\+-14).;./347.+18*):1;-*0-975/)936.+:4*,80987(887(0(*)4.*""/4,4*8+4(((6264826668865:\+;4/4-4+8-4)0(8)6365678469.;88)1/(6*6,6.60626466686:8)8-8*818.8582/9863(+;/""*6,6.6\0626466686:4(8)8-8*818.8582/9863(+;/,6.60626466686:8-818.8582/9864*4+4(0())+;/.6062\6466686:8/8380/7844,4-4*4+4(0())69+;/0626466686:818582/9864.4/4,4-4*4+4(0())+;" [e+E+e+t]-40; E+=s+s; } n(45){ if(T>i) { v(2,T,7); v(46,T,7); } v(2+T,44,7); } T=0; o(e,42)o(t,m)h[T][e][t]--; while(R+i) { s = D=0; if (r-R) { n(19) if (G[R+i][T]+i) V=T/2; else if(G[R][T]+i) s++; if(s) { if(V>4){ V=9-V; D++; } V+=29; n(20) q(c[V][T][0],c[V][T][i],D); } } n(19) if((L=G[R][T])+i) { O=T-L; e=O>9; t=e?18-O :O; o(K,((t&3)-3?16:37)){ if(K){ L=c[t+19][K-i][0]; O=c[t+19][K-i][i] ; } q(L,O,K && e); } } if(s) q(c[V][20][0], c[V][20][i], D); R--; } printf("\33[47;1f\33[?25h\33[40m"); return 0; }
and what program do i use to chuck that code into?
oh wait so i need the program C to put this code in? or i chuck this into excel cell?
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