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CosmicCowboy
08-21-2012, 11:21 AM
one of those stupid ones where if you answer it it sends it to all your friends and there were like 250,000 answers most of which were wrong. I LMAO'd at the majority of people that were ridiculing the people that got the right answer...

soooo, here it is...

6 -1 X 0 + 2 ÷ 2 = ?

DisAsTerBot
08-21-2012, 11:24 AM
order of operations

























7

coyotes_geek
08-21-2012, 11:26 AM
7

CosmicCowboy
08-21-2012, 11:27 AM
Yeah, this is typically a brighter crowd than facebook even if some of you are politically fucked up...:lol

boutons_deux
08-21-2012, 11:28 AM
6 -(1 x 0) + (2 ÷ 2)

6 - 0 + 1

CosmicCowboy
08-21-2012, 11:30 AM
Damn! So Boutox can be rational when he does math?

CosmicCowboy
08-21-2012, 11:31 AM
I should have posted it in the club...

coyotes_geek
08-21-2012, 11:33 AM
Damn! So Boutox can be rational when he does math?

Of course boutonsbot can do math. Anything between negative infinity and positive infinity is the republicans fault.

baseline bum
08-21-2012, 11:37 AM
Of course boutonsbot can do math. Anything between negative infinity and positive infinity is the republicans fault.

I thought he worked exclusively along the imaginary axis?

coyotes_geek
08-21-2012, 11:38 AM
I thought he worked exclusively along the imaginary axis?

:lol

touche'

Spurminator
08-21-2012, 11:42 AM
And if the Republicans get their way, Operations will be deregulated.

That's not to say I agree with Obama's constant demonizing of Division for its supposedly unfair advantage.

TeyshaBlue
08-21-2012, 12:08 PM
Lends a whole new meaning to 1%!

CosmicCowboy
08-21-2012, 12:11 PM
And if the Republicans get their way, Operations will be deregulated.

That's not to say I agree with Obama's constant demonizing of Division for its supposedly unfair advantage.

:lmao

LnGrrrR
08-21-2012, 12:13 PM
one of those stupid ones where if you answer it it sends it to all your friends and there were like 250,000 answers most of which were wrong. I LMAO'd at the majority of people that were ridiculing the people that got the right answer...

soooo, here it is...

6 -1 X 0 + 2 ÷ 2 = ?

Please pity my dear Aunt Sally...

6 + (-1 x 0) + (2 / 2) =

6 + 0 + 1 = 7

7, good sir.

LnGrrrR
08-21-2012, 12:14 PM
Also, if boutons works along the imaginary axis, I can only assume that many Republicans are big fans of policies which resemble the square root of -1. :D

DPG21920
08-21-2012, 01:17 PM
3 year old Chinese baby is laughing at us right now.

Drachen
08-21-2012, 01:23 PM
LOL, there is another one just like this (where a "*0" towards the end fucks everyone up). It makes me sad.

Also, Lngrr, Please Pity my dear aunt sally?

I had always heard "excuse" for exponent
what does pity stand for?

LnGrrrR
08-21-2012, 01:44 PM
LOL, there is another one just like this (where a "*0" towards the end fucks everyone up). It makes me sad.

Also, Lngrr, Please Pity my dear aunt sally?

I had always heard "excuse" for exponent
what does pity stand for?

Parentheses/powers. *shrug* I guess "Please excuse" would be Parentheses/exponents. :)

Drachen
08-21-2012, 02:05 PM
Parentheses/powers. *shrug* I guess "Please excuse" would be Parentheses/exponents. :)

Ok Powers. I didn't say it was wrong I was just trying to think of a P word which would make it correct. Thanks!

baseline bum
08-21-2012, 02:13 PM
Should I put this problem on facebook: Given any e > 0, show there is a positive number C(e) such that for all nonzero relatively prime integers a,b,c with c = a+b, we have

max{|a|, |b|, |c|} <= C(e)N_0(abc)^{1+e},

where N_0(abc) is the product of all primes dividing abc.

tlongII
08-21-2012, 02:20 PM
Should have posted this in the NBA Forum and seen what answers Laker fans come up with.

ElNono
08-21-2012, 03:05 PM
should i put this problem on facebook: Given any e > 0, show there is a positive number c(e) such that for all nonzero relatively prime integers a,b,c with c = a+b, we have

max{|a|, |b|, |c|} <= c(e)n_0(abc)^{1+e},

where n_0(abc) is the product of all primes dividing abc.

42

LnGrrrR
08-21-2012, 03:31 PM
Should I put this problem on facebook: Given any e > 0, show there is a positive number C(e) such that for all nonzero relatively prime integers a,b,c with c = a+b, we have

max{|a|, |b|, |c|} <= C(e)N_0(abc)^{1+e},

where N_0(abc) is the product of all primes dividing abc.

Those are letters. You can't do math with letters. Trick question.

Th'Pusher
08-21-2012, 03:34 PM
42

I'm gonna need to see your work on that.

ElNono
08-21-2012, 03:41 PM
I'm gonna need to see your work on that.

here (http://en.wikipedia.org/wiki/42_(number)#The_Hitchhiker.27s_Guide_to_the_Galaxy )

Wild Cobra
08-21-2012, 04:02 PM
Damn! So Boutox can be rational when he does math?
LOL...

Probably the only time he's not irrational.

I wonder if he can handle irrational numbers, or if they are too much competition for him?

Sportcamper
08-21-2012, 04:06 PM
Should have posted this in the NBA Forum and seen what answers Laker fans come up with.

Pretty sure this equation was used by Blazer management to explain drafting Oden over Durant….