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1369
02-01-2007, 11:27 AM
A buddy just sent me an email with a pic of a check some smartass wrote to Verizon with the amount filled out in some sort of scientific equation. Anyone here willing to post the pic and tell me what the amount is for?

I think in college I was supposed to take this type of math class, but I looked at the requirements, said "shit on this", went over to George's Bar and drank beer.
1369
02-01-2007, 11:34 AM
Nevermind on the help posting, here it is:

http://i127.photobucket.com/albums/p151/equato/verizoncheck-mum-the-weiser.jpg
zero signal
02-01-2007, 11:37 AM
"What now bitches?" :lmao

Well, the sum is about $1, and the exponential looks imaginary, so I'd say about $1.002?
zero signal
02-01-2007, 11:44 AM
Or, is there a joke that went over my head in there? :lol
Shelly
02-01-2007, 11:55 AM
If that's real, that's pretty funny! :lol
tlongII
02-01-2007, 12:27 PM
I think it's about a dollar. However, I'm not sure what the "e" is supposed to represent. I also can't tell what power it is raised to. I can see that pi is part of it, but I can't tell what it's being multiplied by?
MoSpur
02-01-2007, 01:03 PM
That is too funny.
shelshor
02-01-2007, 01:40 PM
I think it's about a dollar. However, I'm not sure what the "e" is supposed to represent. I also can't tell what power it is raised to. I can see that pi is part of it, but I can't tell what it's being multiplied by?
Tho the details are dimmed by the mists of antiquity, I think "e" is the natural logarithm of 2
zero signal
02-01-2007, 02:00 PM
I think it's about a dollar. However, I'm not sure what the "e" is supposed to represent. I also can't tell what power it is raised to. I can see that pi is part of it, but I can't tell what it's being multiplied by?

It's an i, probably for sqrt(-1).

Which is pretty damned funny on a real check. :tu
Nbadan
02-01-2007, 02:25 PM
Hint:

e^i(pie) = int (pie) i
AlamoSpursFan
02-01-2007, 02:34 PM
"I'll be watching the news...and if anything is vandalized or explodes or catches on fire "x" is gonna equal me kicking your ass!" -- Red Foreman

:lol
baseline bum
02-01-2007, 03:19 PM
Nevermind on the help posting, here it is:

http://i127.photobucket.com/albums/p151/equato/verizoncheck-mum-the-weiser.jpg

e^(i*pi) = cos(pi)+i*sin(pi) = -1 + i*0 = -1 (can be proved by taking Taylor Series of e^(ix))

1+1/2+1/4+1/8+... = 1/(1-1/2) = 2

$0.002 + $e^(pi*i) + $(1/2+1/4+1/8+...) = $0.002 + $-1 + $(2-1) = $0.002

Ie, the check is for 2/10th of a cent.

Pretty stupid... if he really wanted to be a prick, he should have put a contour integral on the check.
TheSanityAnnex
02-01-2007, 03:32 PM
Randall Patrick Munroe is my hero.
Nbadan
02-01-2007, 04:11 PM
e^(i*pi) = cos(pi)+i*sin(pi) = -1 + i*0 = -1 (can be proved by taking Taylor Series of e^(ix))

1+1/2+1/4+1/8+... = 1/(1-1/2) = 2

$0.002 + $e^(pi*i) + $(1/2+1/4+1/8+...) = $0.002 + $-1 + $(2-1) = $0.002

Ie, the check is for 2/10th of a cent.

Pretty stupid... if he really wanted to be a prick, he should have put a contour integral on the check.

Nice...how is it you only have $25 in v-bookie cash again?
1369
02-01-2007, 04:19 PM
You sure that shouldn't be two thousandths of one cent?
baseline bum
02-01-2007, 04:26 PM
You sure that shouldn't be two hundreths of one cent?

Yes

$0.002 = 0.002 dollar * 100 cents/dollar = 0.2 cents = 2/10 cents = 2/10 of a cent
1369
02-01-2007, 04:28 PM
Missed the $ sign.

In my industry (heavy construction) 0.002 would read two thousandths (as in inches).
2Blonde
02-01-2007, 04:31 PM
You sure that shouldn't be two thousandths of one cent?
No, $0.02 would be two cents, so $0.002 would be two tenths of a cent.
2Blonde
02-01-2007, 04:32 PM
Oops, sorry I didn't see the reply
Spurminator
02-01-2007, 04:33 PM
This should clarify things for you guys.
http://media.putfile.com/Verizon-Bad-Math

Originally posted here:
http://www.spurstalk.com/forums/showthread.php?t=56149&highlight=verizon
Nbadan
02-01-2007, 04:44 PM
http://media.putfile.com/Verizon-Bad-Math

Classic!

:lol
Johnny_Blaze_47
02-01-2007, 04:46 PM
Somehow, I've got to work "What now, bitches?" into my daily routine.
1Parker1
02-01-2007, 09:00 PM
:lmao @ this check....
FromWayDowntown
02-01-2007, 11:34 PM
Somehow, my desire to reduce fractions on my checks doesn't seem quite so rebellious.
zero signal
02-01-2007, 11:38 PM
e^(i*pi) = cos(pi)+i*sin(pi) = -1 + i*0 = -1 (can be proved by taking Taylor Series of e^(ix))
Crap, that's Euler's law. I'm a EE major, I'm supposed to know that. :depressed
KEDA
02-01-2007, 11:40 PM
Joe used his abacus to figure out how much it was.
Fillmoe
02-01-2007, 11:44 PM
verizon should hire randall patrick munroe
baseline bum
02-02-2007, 02:32 AM
Crap, that's Euler's law. I'm a EE major, I'm supposed to know that. :depressed

You should get to know it well, because the formulas:

sin(x) = (e^(ix)-e^(-ix))/(2i)

and

cos(x) = (e^(ix) + e^(-ix))/2

are two of the most useful things for doing any kind of trig problem (especially in problems involving angle addition), and they come up all the time in PDEs and ODEs.