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I ain't touching 'em, these are pure stat, not probability, and I forgot that 20 years ago. I hope BB needs your money.
20 bucks to the first person to finish via paypal. And no, I won't just take the answers and not pay, I will pay. Kori can ban my ass if the first to finish (correctly) doesn't receive their money. I'm pretty much offering Baseline Bum 20 bucks cause he seems good at stats.
(1) Suppose you are interested in estimating the actual amount of Pepsi that is placed in 2-liter bottles. Pepsi-Co has informed you that the population of Pepsi bottles is distributed normally with a mean of 2.00 liters and a standard deviation of 0.05 liters. What is the probability that that one bottle drawn at random will contain more than 2.07 liters or less than 1.97 liters?
For the next two questions, suppose you are interested in Coca-Cola instead of Pepsi. However, this time you do not know the sample mean for the Coke bottles you are testing.
(2) Suppose that the population standard deviation for the amount of liquid in a Coke bottle is 0.03. Suppose you take a sample of 20 bottles drawn at random whose sample mean is 1.02. Find a 90% confidence interval for the true population mean. (Hint: use normal distribution)
(3) Suppose you do not know the population standard deviation for the amount of liquid in a Coke bottle. Instead, you take a sample of 20 bottles drawn at random and find that the sample mean is 1.02 and the sample standard deviation is 0.03. Find a 90% confidence interval for the true population mean. (Hint: use Student’s t distribution)
(4) The personnel department of a business would like to estimate the family dental expenses of its employees to determine the feasibility of providing a dental insurance plan. A random sample of 10 employees reveals the following family dental expenses (in dollars) for the preceding year:
110, 362, 246, 85, 510, 208, 173, 425, 316, 179
Find a 95% confidence interval for the population proportion of family dental expenses that are above $300 (Hint: use the Normal distribution for proportions).
(5) Suppose you are performing a blind taste test for carbonated beverages and you want to see how Dr. Pepper scores against other soft drinks. You ask people to try different soft drinks and then provide a score (out of 100) for Dr. Pepper against the other types of soft drinks. How many people would you have to survey if the mean score is to be estimated within plus or minus 2 of the true population mean when the standard deviation is 15? Use a 94% level of confidence.
I ain't touching 'em, these are pure stat, not probability, and I forgot that 20 years ago. I hope BB needs your money.
20 bucks isnt gonna be worth my time wasted doing them.... you gotta offer more than that....
Sorry! I'm too dumb to ever be able to figure out the answers for ya!
If you can't do them in under an hour, then yeah, it is a waste of your time.
sample testing hahahah
fok that
talk about a failure...
42
talk about not having the ability to make 20 bucks...
You're an English major and ahve to take Math, that sounds lame and a waste of time for you. I have yet to take stats, but this looks tedious. I'd do it, if I knew how.
This is for Business.
Thought you were an English major.
I'm taking the exact same course right now and the only problem I could help you with might be the second one. Now I'm not so sure.
1 ).
Sample = 100
The p-value of the test is less than 5%, so the bottles actually con-
tain less than 2 liters
The large sample size caused a difference of
5 ml (0.05 l) to be significant when it really
isn’t practically significant to the consumer,
i.e., we couldn’t tell the difference even by
looking at the bottles
Last edited by lefty; 03-24-2008 at 01:15 AM.
Work through them yourself and you actually might learn something. It's just subs uting numbers into formulae anyway, so get to it!
Since a whole variety of other statistics are based on normal distributions, you'll actually find this stuff useful in understanding every day life.
0.05L = 50mL
This is high-school stats, very simple stuff. Just apply proper formula.
http://en.wikipedia.org/wiki/Confidence_interval
Just use the distribution probability function for normal distributions. Or use tables. Because of the way a ulative distribution function works you just take the difference between the upper and lower bounds for the data.
When data is given you calculate the expectation/variance manually and do the same thing to get a confidence interval.
Anyways, pretty elementary stats. I don't like doing other people's work.
your 20 bucks wont cover the medical fees that i need once i number crunch that into my brain
already doing these problems..... But I need to make sure my work is correct. I hate stats.
And must you always follow Ruff like a dog hunting a bone? Give it a rest already.
I'll do number 1 and donate my share to Duff so he can repay Jim.
In this problem 1.97 corresponds to a Z value of -0.6
(1.97 - 2.00) / 0.05 = -0.6
2.07 corresponds to a Z value of 1.4
(2.07 - 2.00) / 0.05 = 1.4
The probability that a random bottle has less than 1.97 = P(Z < -0.6)
The probability that a random bottle has more than 2.07 = P(Z > 1.4)
Using this table (which shows the probability distribution function p(z) = P(Z < z) ):
http://math2.org/math/stat/distributions/z-dist.htm
P(Z < -0.6) = p(-0.6) = 0.27425
P(Z > 1.4) = P(Z < -1.4) = p(-1.4) = 0.08076
The probability that that one bottle drawn at random will contain more than 2.07 liters or less than 1.97 liters is:
P(Z < -0.6) + P(Z > 1.4) = 0.27425 + 0.08076 = 0.35501
Exactly.And must you always follow Ruff like a dog hunting a bone? Give it a rest already.
Why don't you just leave me alone? I've asked you how many times?
closed.
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