lo deehi - hi deelo
lo squared
=
[16-5 (0) - 0 (d/dx 16-5)] / [16-5]^2
=
[11 (0) - 0(0)] / [16-5]^2
=
0/121
=
0
(the net value of this thread)
[Kobe (rings) - Duncan (rings)]
-------------------------------------
LAL - SAS
lo deehi - hi deelo
lo squared
=
[16-5 (0) - 0 (d/dx 16-5)] / [16-5]^2
=
[11 (0) - 0(0)] / [16-5]^2
=
0/121
=
0
(the net value of this thread)
Chain rule? You had it set up as a quotient. WTF
In any case, you'll get a zero for the answer so it's a moot point. Unless you want to count Kobe (k) and Duncan (t) as variables, in which case you're talking implicit differentiation which is calc 2 and leads to a stupid answer which makes no sense.
{
JOptionPane.showMessageDialog("Go to bed... and re-take calculus next semester");
System.exit(0);
}
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