Those 5 guys will never be on the court at the same time, playing for the same team.
Don't know about Kobe and Shaq but I do know a lineup of Kobe, Artest, Odom, Gasol and Bynum is getting at least two more, do it Buss, give Lamar a guaranteed forth year and lets party!!!
Those 5 guys will never be on the court at the same time, playing for the same team.
Why not? Spacing? GTFO. That lineup will own all comers on both ends.
'Cause Jackson never put Odom, Pau and Bynum at the same time this past season and he won the NBA championship, so I doubt he'll change that now.
You're right, he'll probably never do it. I know a ton of Laker fans were calling for that LO, Pau, Bynum FC all year but we only saw it for a couple preseason games. The only reason I think that lineup may happen is if the Lakers do resign Lamar and then Bynum develops really well and he wants to be out there to end games, which he complained about last year before getting hurt, and then Lamar is left out and I'm sure Lamar would be pissed. So the only way to get him back out there to end games is to put him at the three and then Ron the two and Kobe the one, IDK I think that lineup would own but Jackson probably won't do it unless he absolutely has to to make Lamar and Bynum happy.
only 1. the one that Kobe got his wife after the rape
Ya mook, you. You can't purchase something like that off the rack.
zero more. If they had kept Shaq, they would lost Kobe. No way did he want to play with Shaq anymore. He wanted to prove to the world he was Jordan, but he has to win 5 more championships to be in that category. Right now he only has 1.
tee, hee. It was ok when he was stuck on 3, huh? Now that only the one charter left Florida for California back a month ago you moved the bar back to 1.
Bomb diggity.
It's not given a *. Phil Jackson mentioned that in an interview the next season and everyone assumes its an official NBA thing. Its not, its one man's opinion and the sheep who bleat in agreement.
lmao!!!!!!!
There are currently 1 users browsing this thread. (0 members and 1 guests)