However, this is from your source. It shows that McDonald is wrong about division leader being a tiebreaker for 2 way ties. So, McDonald is wrong.
http://www.nba.com/statistics/playoff_picture.html
a. Two Teams Tied
(1) Better winning percentage in games against each other.
(2) Better winning percentage against teams in own division (only if tied teams are in same division).
(3) Better winning percentage against teams in own conference.
(4) Better winning percentage against teams eligible for playoffs in own conference (including teams that finished the regular season tied for a playoff position).
(5) Better winning percentage against teams eligible for playoffs in opposite conference (including teams that finished the regular season tied for a playoff position).
(6) Better net result of total points scored less total points allowed against all opponents (“point differential”).
b. More Than Two Teams Tied
(1) Better winning percentage in all games among the tied teams.
(2) Better winning percentage against teams in own division (only if all tied teams are in the same division).
(3) Better winning percentage against teams in own conference.
(4) Better winning percentage against teams eligible for playoffs in own conference (including teams that finished the regular season tied for a playoff position).
(5) Better net result of total points scored less total points allowed against all opponents (“point differential”).
Since this is from that source, is current, then it appears that the 2 way tiebreaker is not broken through one team being a division leader.
