Wow, lets see, here's an educted guess...
Keep in mind, you didn't say how large of a puddle... Apply proportional math.
I was exposed to as much as maybe a 10 square feet of surface material at a time after a cell blew, and we were in cleanup. We could get no close than about 5 feet away. All we wore was cotton only clothing. Jeans and shirts, no special clothing. Just very long steel tools. I would say triple that for the same exposed area would be 15 feet, except I made a serious error... I'm going to revise my last post after this one. Emissivity plays a larger role than I thought. For molten aluminum, it is 0.12. For molten steel, it is 0.4, and for fire it is 0.8. My prior calculations were set at the default 1.0. At least emissivity is a linear relationship. With steel at 3 times that of aluminum, at the melting point. This makes that ~10:1 ratio of heat to be 28.85:1. Distance requirements are now more than 5 times greater for molten steel than aluminum.
I don't know how hot the reduction cells ran at. We operated only slightly above melting in the foundry, were I saw temperature gauges. Always mid 1200's F. (melts at 1220 F). I would venture to guess, the converted cells operate at about 800 C to 900 C, even though wiki says:. My reason is that we converted to the 4.3 volt lower temperature/power setup, and wiki probably uses the 4.7 volt. We were running 99.9999+% pure aluminum under the 4.7 volts, but the purity dropped under the lower voltage. Hard to really say for sure, but for argument, I will use the 980. This will reduce the ratio rather than accidentally increasing it. Just being conservative... That's allot of savings of power and reduction of heat to reduce the voltage.The operational temperature of the reduction cells is around 950 to 980 °C
Molten aluminum at 660 C = 9333 K = 1,641 watts/meter of heat
Molten aluminum at 980 C = 1253 K = 5,339 W/m (my probable experience)
Molten Steel at 1370 C = 1643 K = 52,612 W/m.
Molten steel at 1427 C = 1700 K = 60,301 W/m. (a little higher than melting)
OK, it's still close to a 10:1 ratio (accidentally) and I would say a person just wearing heavy plain clothing would need to be at least 15 ft. away from an exposed area of molten steel of about 10 square feet. The hotter you make it, or the larger the surface area, the farther away. Aluminum at just melting would be 1641 watts. Back to the greater than 5:1 ratio for distance from the same exposed area between steel and aluminum at the melting point.
Appropriate graphs:
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