math problem that showed up on facebook...

[CosmicCowboy]

one of those stupid ones where if you answer it it sends it to all your friends and there were like 250,000 answers most of which were wrong. I LMAO'd at the majority of people that were ridiculing the people that got the right answer...

soooo, here it is...

6 -1 X 0 + 2 ÷ 2 = ?

[DisAsTerBot]

order of operations

























7

[coyotes_geek]

7

[CosmicCowboy]

Yeah, this is typically a brighter crowd than facebook even if some of you are politically ed up...

[boutons_deux]

6 -(1 x 0) + (2 ÷ 2)

6 - 0 + 1

[CosmicCowboy]

Damn! So Boutox can be rational when he does math?

[CosmicCowboy]

I should have posted it in the club...

[coyotes_geek]

Damn! So Boutox can be rational when he does math?

Of course boutonsbot can do math. Anything between negative infinity and positive infinity is the republicans fault.

[baseline bum]

Of course boutonsbot can do math. Anything between negative infinity and positive infinity is the republicans fault.

I thought he worked exclusively along the imaginary axis?

[coyotes_geek]

I thought he worked exclusively along the imaginary axis?

touche'

[Spurminator]

And if the Republicans get their way, Operations will be deregulated.

That's not to say I agree with Obama's constant demonizing of Division for its supposedly unfair advantage.

[TeyshaBlue]

Lends a whole new meaning to 1%!

[CosmicCowboy]

And if the Republicans get their way, Operations will be deregulated.

That's not to say I agree with Obama's constant demonizing of Division for its supposedly unfair advantage.

[LnGrrrR]

one of those stupid ones where if you answer it it sends it to all your friends and there were like 250,000 answers most of which were wrong. I LMAO'd at the majority of people that were ridiculing the people that got the right answer...

soooo, here it is...

6 -1 X 0 + 2 ÷ 2 = ?

Please pity my dear Aunt Sally...

6 + (-1 x 0) + (2 / 2) =

6 + 0 + 1 = 7

7, good sir.

[LnGrrrR]

Also, if boutons works along the imaginary axis, I can only assume that many Republicans are big fans of policies which resemble the square root of -1.

[DPG21920]

3 year old Chinese baby is laughing at us right now.

[Drachen]

LOL, there is another one just like this (where a "*0" towards the end s everyone up). It makes me sad.

Also, Lngrr, Please Pity my dear aunt sally?

I had always heard "excuse" for exponent
what does pity stand for?

[LnGrrrR]

LOL, there is another one just like this (where a "*0" towards the end s everyone up). It makes me sad.

Also, Lngrr, Please Pity my dear aunt sally?

I had always heard "excuse" for exponent
what does pity stand for?

Parentheses/powers. *shrug* I guess "Please excuse" would be Parentheses/exponents.

[Drachen]

Parentheses/powers. *shrug* I guess "Please excuse" would be Parentheses/exponents.

Ok Powers. I didn't say it was wrong I was just trying to think of a P word which would make it correct. Thanks!

[baseline bum]

Should I put this problem on facebook: Given any e > 0, show there is a positive number C(e) such that for all nonzero relatively prime integers a,b,c with c = a+b, we have

max{|a|, |b|, |c|} <= C(e)N_0(abc)^{1+e},

where N_0(abc) is the product of all primes dividing abc.

[tlongII]

Should have posted this in the NBA Forum and seen what answers Laker fans come up with.

[ElNono]

should i put this problem on facebook: Given any e > 0, show there is a positive number c(e) such that for all nonzero relatively prime integers a,b,c with c = a+b, we have

max{|a|, |b|, |c|} <= c(e)n_0(abc)^{1+e},

where n_0(abc) is the product of all primes dividing abc.

42

[LnGrrrR]

Should I put this problem on facebook: Given any e > 0, show there is a positive number C(e) such that for all nonzero relatively prime integers a,b,c with c = a+b, we have

max{|a|, |b|, |c|} <= C(e)N_0(abc)^{1+e},

where N_0(abc) is the product of all primes dividing abc.

Those are letters. You can't do math with letters. Trick question.

[Th'Pusher]

42

I'm gonna need to see your work on that.

[ElNono]

I'm gonna need to see your work on that.

here